day 2b solved!
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6 changed files with 213 additions and 2 deletions
1
aoc-2b/src/example.txt
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1
aoc-2b/src/example.txt
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11-22,95-115,998-1012,1188511880-1188511890,222220-222224,1698522-1698528,446443-446449,38593856-38593862,565653-565659,824824821-824824827,2121212118-2121212124
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1
aoc-2b/src/input.txt
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aoc-2b/src/input.txt
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5959566378-5959623425,946263-1041590,7777713106-7777870316,35289387-35394603,400-605,9398763-9592164,74280544-74442206,85684682-85865536,90493-179243,202820-342465,872920-935940,76905692-76973065,822774704-822842541,642605-677786,3759067960-3759239836,1284-3164,755464-833196,52-128,3-14,30481-55388,844722790-844967944,83826709-83860070,9595933151-9595993435,4216-9667,529939-579900,1077949-1151438,394508-486310,794-1154,10159-17642,5471119-5683923,16-36,17797-29079,187-382
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148
aoc-2b/src/main.rs
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148
aoc-2b/src/main.rs
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// within certain rnages, find numbers with a pattern repeated exactly twice
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// eg "55" ("5" twice), "6464" ("64" twice), "123123"
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// cannot be matches on numebrs with an odd number of digits
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// compare the first half of the didgits to the second half
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// save all the matches (invalid id's) to a list and add them up to produce the solution
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// each rnage can have 0 or more invalid id's
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// need to parse each range (probably regex), get start and end value for each
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use std::fs;
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use regex::Regex;
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fn main() {
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println!("Lets begin, day 2, part 1");
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let file_path = "src/input.txt";
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// let file_path = "src/example.txt";
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// split up input by "," and "-"
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// (?<start_range>\d*)-(?<end_range>\d*)
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let re = Regex::new(r"(?<start_range>\d*)-(?<end_range>\d*)").unwrap();
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let line = fs::read_to_string(file_path).unwrap();
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println!("{line}");
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let mut invalids: Vec<i64> = Vec::new();
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// parse the provided ranges into paits
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let ranges: Vec<(&str, &str)> = re.captures_iter(&line).map(|caps| {
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let start = caps.name("start_range").unwrap().as_str();
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let end = caps.name("end_range").unwrap().as_str();
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(start, end)
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}).collect();
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println!("{ranges:?}");
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for range in ranges{
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println!("working on: {range:?}");
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let start = range.0.parse::<i64>().unwrap();
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let end = range.1.parse::<i64>().unwrap();
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// println!("{range.0:?} --> {end}");
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let mut count :i64 = start;
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while count <= end{
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// if odd number of didgits, then no match, skip to next loop
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// if even number, then compare the first and second half
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let current = count.to_string();
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if find_invalid(current){
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invalids.push(count);
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}
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// if current.len() % 2 != 1{
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// let half_len = current.len()/2;
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// let half_a = ¤t[..half_len];
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// let half_b = ¤t[half_len..];
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// let current_str = current.to_string();
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// println!("{current_str} = {half_a} + {half_b}");
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// if half_a == half_b{
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// invalids.push(count);
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// }
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// }
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count += 1;
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}
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}
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println!("{invalids:?}");
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let mut solution: i64 = 0;
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for result in invalids{
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solution += result;
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}
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println!("Puzzle Solution: {solution}")
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// Correct :3
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}
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fn find_invalid(text : String) -> bool{
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// let mut invalid = false;
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// 1x matches
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if text.len() > 1{
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let one = text.chars().nth(0).unwrap();
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let mut ones_match = true;
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for char in text.chars(){
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if char == one{
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// good
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}
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else{
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ones_match = false;
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}
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}
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if ones_match{
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return true;
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}
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}
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// 2x matches
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if text.len() == 4{
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if &text[0..2] == &text[2..4]{
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return true;
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}
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}
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else if text.len() == 6{
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if &text[0..2] == &text[2..4] && &text[0..2] == &text[4..6]{
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return true;
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}
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}
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else if text.len() == 8{
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if &text[0..2] == &text[2..4] && &text[0..2] == &text[4..6] && &text[0..2] == &text[6..8]{
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return true;
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}
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}
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else if text.len() == 10{
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if &text[0..2] == &text[2..4] && &text[0..2] == &text[4..6] && &text[0..2] == &text[6..8] && &text[0..2] == &text[8..10]{
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return true;
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}
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}
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// 3x matches
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if text.len() == 6 {
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if &text[0..3] == &text[3..6]{
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return true;
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}
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}
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if text.len() == 9 {
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if &text[0..3] == &text[3..6] && &text[0..3] == &text[6..9]{
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return true;
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}
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}
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// 4x matches
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if text.len() == 8 {
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if &text[0..4] == &text[4..8]{
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return true;
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}
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}
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// 5x matches
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if text.len() == 10{
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if &text[0..5] == &text[5..10]{
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return true;
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}
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}
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return false; // represents no match
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}
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// tried: 36862281460 - too high
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// solved! second attempt
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